(5x^1y^1/4x^-9)*(8/x^-2y^8)

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Solution for (5x^1y^1/4x^-9)*(8/x^-2y^8) equation: 


D( x )

x = 0

x^-2 = 0

x = 0

x = 0

x^-2 = 0

x^-2 = 0

1*x^-2 = 0 // : 1

x^-2 = 0

x naleu017Cy do O

x in (-oo:0) U (0:+oo)

x^-9*(8/(x^-2))*((5*x^1*y^1)/4)*y^8 = 0

x^-9*(8/(x^-2))*((5*x*y)/4)*y^8 = 0

10*x^-6*y^9 = 0 // : 10*y^9

x^-6 = 0

x naleu017Cy do O

x belongs to the empty set

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